Changed layout for more manageable volumes

1 files changed, 0 insertions, 568 deletions

diff --git a/2.1.lyx b/2.1.lyx
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--- a/2.1.lyx
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@@ -1,568 +0,0 @@
-#LyX 2.4 created this file. For more info see https://www.lyx.org/
-\lyxformat 620
-\begin_document
-\begin_header
-\save_transient_properties true
-\origin unavailable
-\textclass book
-\begin_preamble
-\input defs
-\end_preamble
-\use_default_options true
-\maintain_unincluded_children no
-\language english
-\language_package default
-\inputencoding utf8
-\fontencoding auto
-\font_roman "default" "default"
-\font_sans "default" "default"
-\font_typewriter "default" "default"
-\font_math "auto" "auto"
-\font_default_family default
-\use_non_tex_fonts false
-\font_sc false
-\font_roman_osf false
-\font_sans_osf false
-\font_typewriter_osf false
-\font_sf_scale 100 100
-\font_tt_scale 100 100
-\use_microtype false
-\use_dash_ligatures true
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-\use_package amssymb 1
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-\use_package mathtools 1
-\use_package mhchem 1
-\use_package stackrel 1
-\use_package stmaryrd 1
-\use_package undertilde 1
-\cite_engine basic
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-\use_bibtopic false
-\use_indices false
-\paperorientation portrait
-\suppress_date false
-\justification true
-\use_refstyle 1
-\use_formatted_ref 0
-\use_minted 0
-\use_lineno 0
-\index Index
-\shortcut idx
-\color #008000
-\end_index
-\secnumdepth 3
-\tocdepth 3
-\paragraph_separation indent
-\paragraph_indentation default
-\is_math_indent 0
-\math_numbering_side default
-\quotes_style english
-\dynamic_quotes 0
-\papercolumns 1
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-\end_header
-
-\begin_body
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-exerc1[04]
-\end_layout
-
-\end_inset
-
-In the situation depicted in (3),
- what is the value of
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-SUIT(NEXT(TOP))
-\family default
-;
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-NEXT(NEXT(NEXT(TOP)))
-\family default
-?
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer
-\end_layout
-
-\end_inset
-
-
-\end_layout
-
-\begin_layout Enumerate
-4.
-\end_layout
-
-\begin_layout Enumerate
-\begin_inset Formula $\Lambda$
-\end_inset
-
-.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-exerc2[10]
-\end_layout
-
-\end_inset
-
-The text points out that in many cases 
-\begin_inset Formula $\mathtt{CONTENTS(LOC(V))}=\mathtt{V}$
-\end_inset
-
-.
- Under what conditions do we have 
-\begin_inset Formula $\mathtt{LOC(CONTENTS(V))}=\mathtt{V}$
-\end_inset
-
-?
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer 
-\end_layout
-
-\end_inset
-
-
-\family typewriter
-V
-\family default
- must be a valid memory address different from 
-\begin_inset Formula $\Lambda$
-\end_inset
-
-.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-rexerc5[21]
-\end_layout
-
-\end_inset
-
-Give an algorithm that essentially undoes the effect of exercise 4:
- Assuming that the pile is not empty and that its bottom card is face down,
- your algorithm should remove the bottom card and make 
-\family typewriter
-NEWCARD
-\family default
- link to it.
- (This algorithm is sometimes called 
-\begin_inset Quotes eld
-\end_inset
-
-cheating
-\begin_inset Quotes erd
-\end_inset
-
- in solitaire games.)
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer
-\end_layout
-
-\end_inset
-
-
-\end_layout
-
-\begin_layout Enumerate
-If 
-\begin_inset Formula $\mathtt{NEXT(TOP)}=\Lambda$
-\end_inset
-
-,
- let 
-\begin_inset Formula $\mathtt{NEWCARD}\gets\mathtt{TOP}$
-\end_inset
-
-,
- 
-\begin_inset Formula $\mathtt{TOP}\gets\Lambda$
-\end_inset
-
- and terminate.
-\end_layout
-
-\begin_layout Enumerate
-\begin_inset Formula $\mathtt{X}\gets\mathtt{TOP}$
-\end_inset
-
-,
- 
-\begin_inset Formula $\mathtt{Y}\gets\mathtt{NEXT(TOP)}$
-\end_inset
-
-.
-\end_layout
-
-\begin_layout Enumerate
-If 
-\begin_inset Formula $\mathtt{NEXT(Y)}\neq\Lambda$
-\end_inset
-
-,
- let 
-\begin_inset Formula $\mathtt{X}\gets\mathtt{Y}$
-\end_inset
-
-,
- 
-\begin_inset Formula $\mathtt{Y}\gets\mathtt{NEXT(Y)}$
-\end_inset
-
- and repeat this step.
-\end_layout
-
-\begin_layout Enumerate
-Set 
-\begin_inset Formula $\mathtt{NEWCARD}\gets\mathtt{Y}$
-\end_inset
-
- and 
-\begin_inset Formula $\mathtt{NEXT(X)}\gets\Lambda$
-\end_inset
-
-.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-exerc6[06]
-\end_layout
-
-\end_inset
-
-In the playing card example,
- suppose that 
-\family typewriter
-CARD
-\family default
- is the name of a variable whose value is an entire node as in (6).
- The operation 
-\begin_inset Formula $\mathtt{CARD}\gets\mathtt{NODE(TOP)}$
-\end_inset
-
- sets the fields of 
-\family typewriter
-CARD
-\family default
- respectively equal to those of the top of the pile.
- After this operation,
- which of the following notations stands for the suit of the top card?
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-SUIT(CARD)
-\family default
-;
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-SUIT(LOC(CARD))
-\family default
-;
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-SUIT(CONTENTS(CARD))
-\family default
-;
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-SUIT(TOP)
-\family default
-?
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer
-\end_layout
-
-\end_inset
-
-2 and 4.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-rexerc7[04]
-\end_layout
-
-\end_inset
-
-In the text's example 
-\family typewriter
-MIX
-\family default
- program,
- (5),
- the link variable 
-\family typewriter
-TOP
-\family default
- is stored in the 
-\family typewriter
-MIX
-\family default
- computer word whose assembly language name is 
-\family typewriter
-TOP
-\family default
-.
- Given the field structure (1),
- which of the following sequences of code brings the quantity 
-\family typewriter
-NEXT(TOP)
-\family default
- into register A?
- Explain why the other sequence is incorrect.
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-LDA TOP(NEXT)
-\end_layout
-
-\begin_layout Enumerate
-
-\family typewriter
-LD1 TOP
-\begin_inset Newline newline
-\end_inset
-
-LDA 0,1(NEXT)
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer
-\end_layout
-
-\end_inset
-
-2,
- since the first loads the field 
-\family typewriter
-NEXT
-\family default
- from the memory word 
-\family typewriter
-TOP
-\family default
-,
- that only contains the address,
- instead of from the node that 
-\family typewriter
-TOP
-\family default
- points to.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-rexerc8[18]
-\end_layout
-
-\end_inset
-
-Write a 
-\family typewriter
-MIX
-\family default
- program corresponding to steps B1–B3.
-\end_layout
-
-\begin_layout Standard
-\begin_inset ERT
-status open
-
-\begin_layout Plain Layout
-
-
-\backslash
-answer
-\end_layout
-
-\end_inset
-
-
-\end_layout
-
-\begin_layout Standard
-\begin_inset listings
-inline false
-status open
-
-\begin_layout Plain Layout
-
-NEXT  EQU  4:5
-\end_layout
-
-\begin_layout Plain Layout
-
-LLEN  STJ  CHECK
-\end_layout
-
-\begin_layout Plain Layout
-
-      ENTA 0         ;
- B1
-\end_layout
-
-\begin_layout Plain Layout
-
-      ENT1 TOP
-\end_layout
-
-\begin_layout Plain Layout
-
-2H    J1Z  *         ;
- B2
-\end_layout
-
-\begin_layout Plain Layout
-
-      INCA 1         ;
- B3
-\end_layout
-
-\begin_layout Plain Layout
-
-      LD1  0,1(NEXT)
-\end_layout
-
-\begin_layout Plain Layout
-
-      JMP  2B
-\end_layout
-
-\end_inset
-
-
-\end_layout
-
-\end_body
-\end_document